$CH_3-C\equiv CH \xrightarrow{O_3/Zn, H_2O_2} \text{Product}$ The product in the above reaction is

Consider the following reaction sequence:
$CH_3CH_2CH_2CH(Br)CH_2Br + 2NaNH_2 \rightarrow X$
$X \xrightarrow[(ii) (CH_3)_2CHBr]{(i) NaNH_2} Y$
The product $Y$ formed is:

In the molecule $CH_3-C \equiv C-CH=CH_2$,the maximum number of carbon atoms arranged linearly is

Propene and propyne can be distinguished by

The reaction sequence is as follows:
$CH(COOK)=CH(COOK)_{(aq)}$ $\xrightarrow{\text{electrolysis}} X$ $\xrightarrow[Hg^{2+}]{dil. H_2SO_4} Y$; $Y$ is

Identify the alkyne in the following sequence of reactions:
Alkyne $\xrightarrow{\text{H}_2, \text{Lindlar's catalyst}} A$ $\xrightarrow{\text{Ozonolysis}} B \text{ (only)}$
Given that $B$ is obtained from $\text{CH}_2=\text{CH}_2$ via the Wacker process.